<PRE><B>Question 347465</B>
Let the speed at which the man traveled be x


Let his speed had he walked a kilometres faster be y


y = x+1.............Equation(1)


5x = 4.4y...........Equation(2)


Sub y in (2),


5x=4.4(x+1)


5x=4.4x+4.4


0.6x=4.4


x=22/3 km/h


D=ST


D=5*22/3


D=110/3 km


Therefore, he walked at a rate of approximately 7.3 km/h and traveled a 


distance of approximately 36.7 km
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