Question 347648
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Let *[tex \Large x] represent the measure of a side of the square. Then *[tex \Large x\ +\ 1] represents the measure of a side of the triangle.  The perimeter of the square is then *[tex \Large 4x] and the perimeter of the triangle is *[tex \Large 3(x\ +\ 1)].  Since the perimeters are equal:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ =\ 3(x\ +\ 1)]


Solve for *[tex \Large x]





John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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