Question 347694
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Let *[tex \Large x] represent the amount of 10% solution that you have.  Then  *[tex \Large 54\ -\ x] represents the amount of pure acid needed.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.10x\ +\ 54\ -\ x\ =\ 0.2(54)]


Solve for *[tex \Large x] then subtract the value of *[tex \Large x] from 54.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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