Question 347657
1. f(x) is never positive.


This is false since {{{sqrt(1-x^2)}}} is always nonnegative.

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2. 1 is in the domain of f

This is false since x=1 makes the denominator equal to zero.


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3. 0 is in the domain of f


This is true since the input x=0 yields a real number output.

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4. f(x) is never negative.


This is true since {{{sqrt(1-x^2)}}} is always nonnegative.

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5. All negative real numbers are in the domain of f


False. The domain is {{{-1<x<1}}}. So clearly, a number like {{{x=-10}}} is NOT in the domain.

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6. f(x) is never zero.


This is true as the numerator will never equal zero.


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7. All positive real numbers are in the domain of f


False. Again, the domain is {{{-1<x<1}}}




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