Question 347669
{{{a(n)=a(1)+(n-1)d}}}
{{{a(99)=a(1)+98*d=351}}}
{{{a(100)=a(1)+99*d=353}}}
{{{a(100)-a(99)=a(1)+99d-a(1)-98d}}}
{{{a(100)-a(99)=d}}}
{{{d=353-351}}}
{{{d=2}}}
Then,
{{{a(1)+98d=351}}}
{{{a(1)+98(2)=351}}}
{{{a(1)=351-196}}}
{{{a(1)=155}}}
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{{{a(2)=a(1)+d=155+2=157}}}
{{{a(3)=a(1)+2d=155+4=159}}}
I think you see how to get the next 2 values so I'll leave that to you.