Question 347626
First convert both to slope-intercept form, {{{y=mx+b}}}
{{{-(2/3)y+x=9}}}
{{{y-(3/2)x=-6}}}
{{{y=(3/2)x-27/2}}}
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{{{6x+4y=7}}}
{{{4y=-6x+7}}}
{{{y=-(3/2)x+7/4}}}
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Perpendicular lines have slopes that are negative reciprocals,
{{{m1*m2=-1}}}
{{{(3/2)*(-(3/2))=-1}}}
{{{-9/4=-1}}}
No, the lines are not perpendicular.
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