Question 347496
Let the width of the frame be x.
Thus the width of the picture alone is 28 - 2x and the height would be 32 - 2x (notice x width on either side)...
So we set up
(28 - 2x)(32 - 2x) = 192 and solve for x, the width of the frame...
896 - 56x - 64x + 4x^2 = 192
4x^2 - 120x + 704 = 0
x^2 - 30x + 176 = 0
(x - 8)(x - 22) = 0
x = 8 or x = 22
but it can't be 22, so
x = 8 cm