Question 347141
For any triangle,
{{{A+B+C=180}}}
Substitute,
{{{A+(4A)+(5A-19)=180}}}
{{{10A=199}}}
{{{highlight( A=199/10)}}}degrees
.
.
{{{B=4(199/10)}}}
{{{highlight( B=398/5)}}}degrees

.
.
{{{C=5(199/10)-19}}}
{{{C=199/2-38/2}}}
{{{highlight( C=161/2)}}}degrees