Question 346956
A person is biking 8m/s when the bike passes a car.
 The car starts from rest and accelerates at 3m/s.
 How long will it take for the car to catch up with the bike.
:
Let t = time for the car to overtake the bike 
(this also is the time that the car accelerates at 3 m/sec
:
Write a distance equation, both will travel the same distance, dist = speed * time
:
{{{((0 + 3t))/2}}} * t = 8t
Multiply both sides by 2, results:
3t * t = 16t
:
3t^2 = 16
Divide both sides by t
3t = 16
t = {{{16/3}}}
t = 5{{{1/3}}} seconds for the car to catch the bike
;
:
Check this;
Car will accelerate to: 3*5.33 = 16 m/sec
From a standing stop, it's average speed will be half, 8 m/sec
Both will travel 8m/sec for 5.33 min or about 42.7 meters