Question 347036
{{{drawing(300,300,-6,2,-4,4,circle(-5,-2,0.3),circle(-2,-2,0.3),circle(-5,2,0.3),line(-5,-2,-2,-2),line(-2,-2,-5,2),line(-5,2,-5,-2),
locate(-4.75,-2.15,A),
locate(-1.75,-2.15,B),
locate(-4.75,2.55,C),
grid(1),graph(300,300,-6,2,-4,4,0))}}}
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The vertical leg is {{{AC=2-(-2)=4}}}
The horizontal leg is {{{AB=-2-(-5)=3}}}
You can use the Pythagorean theorem to find BC.
{{{BC^2=3^2+4^2}}}
{{{BC=sqrt(9+16)}}}
{{{BC=sqrt(25)}}}
{{{BC=5}}}
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{{{P=AB+BC+AC}}}
{{{P=3+4+5}}}
{{{highlight(P=12)}}}