Question 346961
let the angle be x degrees
the supplement of this angle will be 180-x

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The complement of the angle will be 90-x
supplement of this complement angle  will be 180 - (90-x)
Twice this = 2[180-(90-x)]
Less 36
=2[180-(90-x)]-36
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180-x = 2[180-(90-x)]-36
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180-x= 2[180-90+x]-36
180-x=2[90+x]-36
180-x=180+2x-36
3x=180-180+36
3x=36
x= 12
supplement of 12 = 180-12 = 168