Question 39372
The advantage would be that if the number has a radical sign, you would have to convert in order to solve faster. Also, its a faster way to multiply or add exponents.
{{{sqrt(2)/sqrt(4)}}}
{{{sqrt(2/4)}}}
{{{sqrt(1/2)}}}
{{{1/sqrt(2)}}}
{{{sqrt(2)/2}}}
Faster way:
{{{2^(1/2)/4^(1/2)}}}
{{{2^(1/2)/2^(1)}}}
{{{2^(1/2-1)}}}
{{{2^(-1/2)}}} or {{{1/2^(1/2)}}} or {{{2^(1/2)/2}}}