Question 346719
0 = x^2 + 2x + 7


Use the quadratic formula:


x = [ -b ± √ ( (b)² - 4(a)(c) ) ] / 2(a) 


x = [ -2 ± √ ( (2)² - 4(1)(7) ) ] / 2(1) 


x = [ -2 ± √ ( 4 - 28 ) ] / 2


x = [ -2 ± √ (- 24 ) ] / 2


x = [ -2 ± 2 √6 i ] / 2


x = [ -1 ± √6 i ]


x = { -1 - √6 i, -1 + √6 i }