Question 346782
5x-3y=-11_x-2y=2

Since -2y does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2y to both sides.
5x-3y=-11_x=2y+2

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is 2y+2.
5(2y+2)-3y=-11_x=2y+2

Multiply 5 by each term inside the parentheses.
10y+10-3y=-11_x=2y+2

Since 10y and -3y are like terms, add -3y to 10y to get 7y.
7y+10=-11_x=2y+2

Since 10 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 10 from both sides.
7y=-10-11_x=2y+2

Subtract 11 from -10 to get -21.
7y=-21_x=2y+2

Divide each term in the equation by 7.
(7y)/(7)=-(21)/(7)_x=2y+2

Simplify the left-hand side of the equation by canceling the common factors.
y=-(21)/(7)_x=2y+2

Simplify the right-hand side of the equation by simplifying each term.
y=-3_x=2y+2

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is -3.
y=-3_x=2(-3)+2

Multiply 2 by each term inside the parentheses.
y=-3_x=-6+2

Add 2 to -6 to get -4.
y=-3_x=-4

This is the solution to the system of equations.
y=-3_x=-4