Question 39302
First rectangle is 4x, and its width is x
Second rectangle is 4x+5 in length and x+2 in width 
Area of first is 4x*x={{{4x^2}}}
Area of second = {{{4x^2+270}}}
EQUATION:
{{{4x^2+270=(4x+5)(x+2)}}}
{{{4x^2+270=4x^2+13x+10}}}
13x=260
x=20
4(20)=80
Hence, the dimensions of the original rectangle are 80cm * 20cm.
Paul.