<PRE><B>Question 346724</B>
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Use the same strategy you use to rationalize a denominator containing a binomial with irrational terms.  Namely, multiply the fraction by 1 in the form of the conjugate of the denominator divided by itself.  The conjugate of your denominator is *[tex \Large -2\ +\ 2i].  Remember when you are doing your arithmetic that *[tex \Large i^2\ =\ -1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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