Question 346697
I'm assuming that the problem is {{{abs(x+4)<6}}}. If so, recall that if {{{abs(x)<a}}}, then {{{x<a}}} or {{{x>-a}}}



Use this idea to break up {{{abs(x+4)<6}}} into {{{x+4<6}}} or {{{x+4>-6}}}. I'll let you take it from here. All you need to do is solve each inequality separately then report the solutions together using "or" as a connective.