Question 346680
{{{(9a^2 - 16)=(3^2a^2-4^2)}}} this is a perfect square
{{{(3a-4)(3a+4)}}}
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{{{3x^3-x^2+6x-2}}} seperate
{{{(3x^3-x^2)+(6x-2)}}} factor what u can from each
{{{x^2(3x-1)+2(3x-1)}}}factor again
{{{(3x-1)(x^2+2)}}}