Question 346645

Let {{{x}}} be the amount of 24% solution.
Let {{{y}}} be the amount of 50% solution.
Volume equation:
1.{{{x+y=100}}}
Concentration equation:
{{{24x+50y=36(x+y)=36(100)=3600}}}
2.{{{12x+25y=1800}}}
From eq. 1,
{{{x=100-y}}}
Substitute into eq. 2,
{{{12(100-y)+25y=1800}}}
{{{1200-12y+25y=1800}}}
{{{13y=600}}}
{{{highlight(y=600/13)}}}gallons
Then from eq. 1,
{{{x+600/13=100}}}
{{{x=1300/13-600/13}}}
{{{highlight(x=700/13)}}}gallons