Question 346523
Use the caret to denote exponentiation, x^2={{{x^2}}}.
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Complete the square in x and y.
{{{x^2 + y^2 - 2x - 12 = 0}}}
{{{(x^2-2x) + (y-0)^2 - 12 = 0}}}
{{{(x^2-2x+1) + (y-0)^2 - 12 = 1}}}
{{{(x-1)^2+ (y-0)^2 = 13}}}
Compare to the general equation for a circle centered at (h,k) with a radius R:
{{{(x-h)^2+(y-k)^2=R^2}}}
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({{{h}}},{{{k}}})=({{{1}}},{{{0}}})