Question 346634
Let A,B, and C be the sides of the triangle, ordered from shortest to longest.
1.{{{A=C-3}}}
2.{{{B=A+2}}}
From eq. 1,
{{{C=A+3}}}
THe perimeter of the triangle is,
{{{A+B+C=20}}}
Substitute,
{{{A+(A+2)+(A+3)=20}}}
{{{3A+5=20}}}
{{{3A=15}}}
{{{highlight( A=5)}}}inches
Then
{{{B=5+2}}}
{{{highlight( B=7)}}}inches
and
{{{C=5+3}}}
{{{highlight( C=8)}}}inches