Question 346529
{{{sqrt(5-x)=x+7}}}
Square both sides.
{{{5-x=(x+7)^2}}}
{{{5-x=x^2+14x+49}}}
{{{x^2+15x+44=0}}}
{{{(x+4)(x+11)=0}}
Two solutions:
{{{x+4=0}}}
{{{highlight(x=-4)}}}
.
.
.
{{{x+11=0}}}
{{{highlight(x=-11)}}}
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.
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As a check, verify the solution by putting them into the original formula and checking that they solve the equation.