Question 346312
"at least one" is the complementary event for "none"


So, we calculate the probability that none of them score a hole-in-one. Then we 


subtract this probability from 1, because if it isn't true that no-one does, 


then at least one of them does.


For each golfer, prob of not scoring hole-in-one


= 1 - 1/2722


= 2721/2722


Hence prob that all 8 fail to do so


= (2721/2722)^8


= 0.997 correct to 3 decimal places.


Therefore, the probability that at least one does


= 1 - 0.997


= 0.003