Question 346361
1. Basketball team lost 40% of its first 40 games.
 how many of its remaining 20 games must it win to raise its winning percentage to 65%?
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Let x = no. of remaining games that need to be won for a winning percent of 65
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Find how many game already lost: .4(40) 16 games lost
then 40 - 16 = 24 games won so far
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Total games played 40 + 20 = 60
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Games won/total games: 
{{{(x+24)/60}}} = .65
multiply both sides for 60
x + 24 = 60 * .65
x + 24 = 39
x = 39 - 24
x = 15 games of the remaining games need to be won
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Check the percentage, 24 + 15 = 39 total games won
{{{39/60}}} = .65 *100 = 65%
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2. Write an equation for each statement;
The sum of 3 numbers is 94,
x + y + z = 94
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 the first number is 3/5 of the second number
x = {{{3/5}}}y
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 the second number is 4/3 of the third.
y = {{{4/3}}}z
We want z to be in terms of y also
Mult both sides by 3
4z = 3y
divide both sides by 4
z = {{{3/4}}}y
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Go back to the 1st equation: x + y + z = 94
Replace x and z
{{{3/5}}}y + y + {{{3/4}}}y = 94
Get rid of those annoying denominators, multiply each term by 20, results
4(3)y + 20y + 5(3)y = 20(94)
12y + 20y + 15y = 1880
47y = 1880
y = {{{1880/47}}}
y = 40
Find x
x = {{{3/5}}}*40
x = 24
Find z
z = {{{3/4}}}*40
z = 30
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See if this is true: 24 + 40 + 30 = 94, so it's ok
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What are the three numbers? 24, 40, 30
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3. In one bag of chicken feeds, there are 24 chickens eating it in 45 days.
 In how many days do 15 chickens consume the feeds?
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Let's coin a term called "chicken-days"
It takes: 24 * 45 = 1080 chicken-days to consume 1 bag of feed
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Let d = no. of days required by 15 chickens, a simple equation
15d = 1080
d = {{{1080/15}}}
d = 72 days for 15 chickens to consume a bag 
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I hope this has unconfused you. Could you follow the reasoning on these.
Any questions? let me know in the comment.