Question 346433
mike and adam left a bus terminal at the same time and traveled in opposite directions. Mike's bus was in heavy traffic and had to travel 20mi/hr slower than adams's bus. After 3 hours their buses were 270 miles apart. How fast was each bus going
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Mike DATA:
rate = x-20 mph ; time = 3 hrs ; distance = 3(x-20) miles
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Adam DATA:
rate = x mph ; time = 3 hrs ; distance = 3x miles
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Equation:
distance + distance = 270 miles
3(x-20) + 3x = 270
x-20 + x = 90
2x = 110
x = 55 mph (Adam's rate)
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x-20 = 35 mph (Mike's rate)
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Cheers,
Stan H.