Question 346245
For a rectangle,
1.{{{A=L*W=60}}}
.
.
{{{P=2L+2W=38}}}
2.{{{L+W=19}}}
From eq. 2,
{{{L=19-W}}}
Substitute into eq. 1,
{{{(19-W)W=60}}}
{{{19W-W^2=60}}}
{{{W^2-19W+60=0}}}
{{{(W-15)(W-4)=0}}}
Two solutions:
{{{W-15=0}}}
{{{W=15}}}in
From eq. 1,
{{{L=4}}}in
.
.
.
{{{W-4=0}}}
{{{W=4}}}in
From eq. 1,
{{{L=15}}}in
.
.
.
The rectangle measure 4 inches by 15 inches.