Question 37677
Given the profit equation
P(x) = 0.2x^2 + 300x - 200
we merely plug in x = 500 and get
P(500) = .2(500)^2 + 300(500) - 200 = 50000 + 150000 - 200 = $199800
The x-coordinate of the vertex, and hence of the maximum, is found by -b/2a, but in this case there is no maximum...
I have a feeling that this P(x) equation is written incorrectly since it has no maximum...