Question 346195
The domain is all of the x values where the function is defined. 
The square root is defined only when the argument is not negative.
A function is defined when the denominator is not zero. 
So the square root argument can't be zero either. 
Solve for 
{{{3-x>0}}}
{{{x<3}}}
That's the only restriction.
The domain of the function is then ({{{-infinity}}},{{{3}}}).
{{{graph(300,300,-10,10,-100,300,(27x+1)/sqrt(3-x)))}}}