Question 346125
Let {{{A}}} be the amount of 40% solution.
Let {{{B}}} be the amount of 73% solution.
.
.
Total volume equation:
1.{{{A+B=110}}}
.
.
Concentration equation:
2.{{{40A+73B=46(110)}}}
From eq. 1,
{{{A=110-B}}}
Substitute into eq. 2,
{{{40(110-B)+73B=46(110)}}}
{{{40(110)-40B+73B=46(110)}}}
{{{33B=6(110)}}}
{{{B=(6*110)/(3*11)}}}
{{{highlight(B=20)}}}ml
Then from eq. 1,
{{{A+20=110}}}
{{{highlight(A=90)}}}ml