Question 345656
{{{25^(10x+8)=(1/125)^(4-2x)}}}
{{{(5^2)^(10x+8)=(1/5^3)^(4-2x)}}}
{{{5^(2(10x+8))=(5^(-3))^(4-2x)}}}
{{{5^(2(10x+8))=5^(-3(4-2x))}}}
{{{2(10x+8)=-3(4-2x)}}}
{{{20x+16=-12+6x}}}
{{{14x=-28}}}
{{{highlight(x=-2)}}}