<PRE><B>Question 346076</B>
 State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10x-4 
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# of sign changes in g(x) is 3 ; so 3 or 1 positive Real zeros.
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# of sign changes in g(-x) is 0 ; so no negative Real zeros.
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Fact: There is one positive around x = 0.4606
There are no negative so there are 2 imaginary.
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Cheers,
Stan H.</PRE>