Question 345966
a radiator contains 8 quarts of fluid, 40% of which is antifreeze. how much fluid should be drained and replaced with pure antifreeze so the new mixture is 60% antifreeze
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Equation:
active - active + active = active
0.40*8 - 0.40x + 1.00x = 0.60(8)
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Multiply thru by 100 to get:
40*8 - 40x + 100x = 60*8
60x = 20*8
x = (1/3)8
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x = 2 2/3 quarts (amt. of fluid to replace)
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Cheers,
Stan H.
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