Question 345866
Use the common denominator, {{{x(x-1)=x^2-x}}}
{{{1/(x^2-x)-(x-1)/(x(x-1))=x/(x(x-1))}}}
{{{(1-(x-1)-x)/(x(x-1))=0}}}
{{{(1-x+1-x)/(x(x-1))=0}}}
{{{(2-2x)/(x(x-1))=0}}}
{{{(2(1-x))/(x(x-1))=0}}}
{{{(-2(x-1))/(x(x-1))=0}}}
{{{-2/x=0}}}
No solution.