Question 345586
1.{{{x+y=56}}}
2.{{{x+3y=56}}}
From eq. 1,
{{{y=56-x}}}
{{{3y=168-3x}}}
Substitute into eq. 2,
{{{x+168-3x=56}}}
{{{-2x=-112}}}
{{{highlight(x=56)}}}
Then from eq. 1,
{{{56+y=56}}}
{{{highlight(y=0)}}}