Question 39267
Factor: {{{x^2-3x-2}}}

Try this!
You are looking for two binomials of the form:
{{{(x+m)(x+n)}}} where: {{{m*n = -2}}} and {{{m+n = -3}}}

Let's see what we can find.
If m = 1 and n = -2, then {{{m*n = -2}}} (This is ok) and {{{m+n = -1}}} (but this won't do it).
Try m = -1 and n = 2, then {{{m*n = -2}}} (This is ok)and {{{m+n = 1}}} (but this won't do either).
As you can see, we've exhausted the possibilities of the restriction on m and n, so the conclusion is that the expression:{{{x^2-3x-2}}} is not factorable, therefore, it is prime.