Question 345384
Rate*Time=Distance
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{{{5}}} minutes={{{5/60=1/12}}} hour
So the stray ran ({{{1/12}}}) hour. 
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{{{drawing(300,300,-10,10,-10,10,
locate(-9.0,3.0,t=0),locate(-9.0,-3.0,t=5),
circle(-6.0,3.0,0.3),circle(-2.0,3.0,0.3),circle(2.0,3.0,0.3),line(-6,3,2,3),
locate(-6.0,2.5,S),locate(-2.0,2.5,H),locate(2.0,2.5,X),
circle(-6.0,-3.0,0.3),circle(-2.0,-3.0,0.3),circle(2.0,-3.0,0.3),line(-6,-3,2,-3),
locate(2.0,-3.5,H),locate(2.0,-1.5,S) )}}}
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HX is the distance that the herd moved.
In {{{5}}} minutes, the herd moved,
{{{HX=6(1/12)=1/2}}}mile
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SX is the distance that the stray moved.
In 5 minutes, the stray moved,
{{{SX=10(1/12)}}}
{{{SX=10/12=5/6}}}
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SH is the distance they were intially separated.
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{{{SH+HX=SX}}}
{{{SH+1/2=5/6}}}
{{{SH=5/6-3/6}}}
{{{SH=2/6=1/3}}} mile