Question 345158
Use the Pythagorean theorem,
{{{x^2+(2x+4)^2=(2x+6)^2}}}
{{{x^2+(4x^2+16x+16)=4x^2+24x+36}}}}
{{{5x^2+16x+16=4x^2+24x+36}}}}
{{{x^2-8x-20=0}}}
{{{(x-10)(x+2)=0}}}
Two solutions but only the positive solution makes sense here.
{{{x-10=0}}}
{{{highlight(x=10)}}}
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(10,24,26)