Question 345288


{{{(3x+1)^2=9}}} Start with the given equation.



{{{3x+1=""+-sqrt(9)}}} Take the square root of both sides.



{{{3x+1=sqrt(9)}}} or {{{3x+1=-sqrt(9)}}} Break up the "plus/minus" to form two equations.



{{{3x+1=3}}} or {{{3x+1=-3}}}  Take the square root of {{{9}}} to get {{{3}}}.



{{{3x=-1+3}}} or {{{3x=-1-3}}} Subtract {{{1}}} from both sides.



{{{3x=2}}} or {{{3x=-4}}} Combine like terms.



{{{x=2/3}}} or {{{x=-4/3}}} Divide both sides by {{{3}}} to isolate {{{x}}}.



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Answer:



So the solutions are {{{x=2/3}}} or {{{x=-4/3}}}.