Question 344765
Perpendicular lines have slopes that are negative reciprocals,
{{{m[1]*m[2]=-1}}}
{{{9*m[2]=-1}}}
{{{m[2]=-1/9}}}
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{{{y=-(1/9)x+b}}}
Use the point (0,-7) to solve for {{{b}}}
{{{-7=-(1/9)(0)+b}}}
{{{b=-7}}}
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{{{highlight_green(y=-(1/9)x-7)}}}
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{{{drawing(300,300,-10,10,-15,5,grid(1),circle(0,-7,0.3),graph(300,300,-10,10,-15,5,9x+8,-(1/9)x-7))}}}