Question 344874
Four engineers A,B,C and D have been scheduled for job interviews. The personnel manager has scheduled the four for interview rooms 1,2,3,and 4 respectively. However the manager's secretary does not know this, so assigns them to the four rooms in a completely random fashion. What is the probability that
A. All four end up in the correct rooms? (1/4)^4 = 0.0039
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B. None of the four end up in the correct room? (3/4)^4 = 0.3164
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Cheers,
Stan H.