Question 344750
{{{(x^-1y^2)^-3 / (x^3y^4)^-3}}}
Invert to get rid of the neg 3 exponents, then follow the rules of exponents
{{{(x^3y^4)^3 / (x^-1y^2)^3}}} = {{{(x^9y^12)/ (x^-3y^6)}}} = {{{x^((9+3))y^((12-6))}}} = {{{x^12y^6}}}