Question 344567
Each bearing is a sphere. 
The volume of a sphere is,
{{{V=(4/3)(pi)R^3}}}
{{{V=(4/3)(pi)(0.5)^3}}}
{{{V=0.5236}}}cu.inches
For 100,000 bearings, the volume would be,
{{{V[t]=1000000(0.5236)=52359}}} cu. inches
There are {{{12}}} inches in {{{1}}} foot and {{{12^3}}} cubic inches in {{{1}}} cubic ft.
{{{V[t]=52359/12^3=52359/1728=30.3}}}cubic feet
To find the weight, multiply the volume by the density,
{{{m=rho*V[t]=480*30.3=14544}}} lbs.