Question 342914
{{{x^2/5^2-y^2/2^2=1}}}
For this equation, {{{a^2 = 5^2}}} and {{{b^2 = 2^2}}}. That makes a = 5 and b = 2. Also, in a hyperbola, {{{c^2 = a^2 + b^2}}} so {{{c^2 = 5^2 + 2^2 = 25+4 = 29}}}. That makes {{{c = sqrt(29)}}}.<br>
Eccentricity is c/a do for this hyperbola the eccentricity is {{{sqrt(29)/5}}}