Question 344573
{{{(2/3)n-10=(1/4)n}}} 
just gotta learn how to read the problem and translate it into symbols then solve like normal
{{{(2/3)n-(1/4)n=10}}}
common denom is 12
{{{(8/12)n-(3/12)n=10}}}
8-3=5
{{{(5/12)n=10}}}
multiply by 12
{{{5n=120}}}
{{{highlight(n=24)}}}