Question 344289
if the width of a rectangle is 2x-7 and the area of the rectangle is 32cm^2.
 What is the diagonal?
:
{{{32/(2x-7)}}} = length of the rectangle
:
Find the diagonal
d^2 = {{{(2x-7)^2}}} + {{{(32/(2x-7))^2)}}}
:
d = {{{sqrt(4x^2-28x+49 + (1024/(4x^2-28x+49)))}}}