Question 344548
Let the lenght be L. Let the Wdith be W
{{{AreaOfRectangle = Length * Width}}}
You are told the area = 20 and that the width is length-8
So
{{{20 = L * W}}}
{{{20 = L * (L-8)}}}
{{{20 = L^2 - 8L}}}
{{{0 = L^2 -8L - 20}}}
{{{0 = (L-10)(L+2)}}}
So L is either 10 or -2. Since L cannot be negative, then L=10
Which makes W = 10-8 = 2