Question 344362
1.{{{ int( cx^2, dx, -infinity, infinity )=1 }}}
{{{ int( cx^2, dx, 0, 3)=1 }}}
{{{(c/3)x^3}}} evaluated between {{{x=0}}} and {{{x=3}}}
{{{(c/3)(27^3-0^3)=1}}}
{{{c=1/9}}}
.
.
.
2.{{{F(x)=(cx^3)/3=x^3/27}}}
3. {{{F(3)-F(1)=27/27-1/27=26/27}}}