Question 344400
{{{-sqrt(-25)}}}
First we factor the radicand (the -25):
{{{-sqrt(25*(-1))}}}
The we'll use a property of radicals: {{{sqrt(a*b) = sqrt(a)*sqrt(b)}}} to separate the factors into their own square roots:
{{{-(sqrt(25)*sqrt((-1)))}}}
Since {{{sqrt(25) = 5}}} and {{{sqrt(-1) = i}}}:
{{{-(5*i)}}}
or -5i