Question 39217
c(0,0)
f(0,6) this focus means that the hyperbola has a vertical transverse axis
v(0,-sqrt(7))
a = +-sqrt(7)
c = 6
c^2 = a^2 + b^2
6^2 = (sqrt(7))^2 + b^2
36 = 7 + b^2
29 = b^2
+-sqrt(29) = b
{{{((y^2)/7)-((x^2)/29)=1}}}