<PRE><B>Question 344261</B>
Find three consecutive even integers such that four times the first minus the third is six more than twice the second.
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Note: Even numbers are always a multiple of 2.
You must represent them as multiples of 2.
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1st: 2x
2nd: 2x+2
3rd: 2x+4
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Equation:
4(2x)-(2x+4) = 2(2x+2)+6
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6x-4 = 4x+10
2x = 14
x = 7
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1st: 2x = 14
2nd: 2x+2 = 16
3rd: 2x+4 = 18
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Cheers,
Stan H.
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